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Unformatted text preview: Actually, the dierence in the sky temperature is really due to the dif-ference in the frequency, but giving the values just makes this problem easier. Accounting for just these two factors, S N A effective T sky So the size of the antenna required for 500 MHz would be A 500 = 300 x 300 50 5000 = 900 m 2 or a square antenna of 30 m by 30 m. Another point to be made here is that at the higher frequency, the signal bandwidth would be a factor of 10 narrower, which would reduce the antenna area by 10 = 3 . 16, or one with dimensions of 16.9 m by 16.9 m, an not insignicant reduction. CORNELL UNIVERSITY c WES SWARTZ (09/11/16) 131...
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