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RelativeResourceManager (2) - Name: _ Student number: _ See...

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Name: ____________________ Student number: ______________ Page 3 of 26 Version # 1 Continued on next page See page 2 of the exam for instructions. Questions 1-23 are worth two (2) marks each. 1. Which of the following is the conjugate base of H 2 PO 4 ? (A) PO 4 3 (B) HPO 4 2 (C) H 3 PO 4 (D) H 4 PO 4 + (E) OH 2. Equal sized pieces of sodium, magnesium, and cesium are placed in individual flasks containing water. Predict the order in which you think the metals would react, from most reactive to least reactive . (A) Cs > Na > Mg (B) Mg > Na > Cs (C) Mg > Cs > Na (D) Na > Cs > Mg (E) Cs > Mg > Na Reactivity: Group 1 > Group 2 and increases down a group (follows the ionization energy (IE) trend, whereby the lower the IE, the more reactive the metal is. (Recall Lab 2). A conjugate base has a formula that is different by loss of H + , so the conjugate base of H 2 PO 4 would be HPO 4 2 .
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Name: ____________________ Student number: ______________ Page 5 of 26 Version # 1 Continued on next page 5. Which one of the following is an allowed set of quantum numbers ( n, l, m l , m s ) for an electron? (A) (2, 1, 0, 1) (B) (3, 3, 1, –½) (C) (2, 1, –1, –½) (D) (3, –1, 1, +½) (E) (4, 1, 2, +½) 6. Both X-rays and electrons can form diffraction patterns when interacting with atoms in a solid. What would be the momentum p (in kg m s –1 ) of an electron that had the same wavelength as an X-ray photon with a frequency of 1.5 × 10 18 Hz? (A) 3.1 × 10 7 (B) 3.3 × 10 –24 (C) 2.6 × 10 –26 (D) 1.3 × 10 –42 (E) 3.5 × 10 –54 Refer to data page (p.25) for de Broglie equation ( λ = h / mv = h / p) and mass of an electron (m e = 9.10 × 10 31 kg). λ = h / p we need: p = h / λ Convert the given frequency into wavelength (recall that ν and λ have an inverse relationship, related through the speed of light): λ = c / ν = 2.9979 × 10 8 m/s / 1.5 × 10 18 s 1 λ = 1.9 99 × 10 10 m Now p = h / λ p = (6.626 × 10 34 J s ) / (1.9 99 × 10 10 m) p = 3.3 1 × 10 24 J s m 1 or kg m s –1 Note (data page): 1 J = 1 kg m 2 s 2 , therefore J s m 1 = kg m 2 s 2 × s m 1 = kg m s –1 Boundaries on n: n = 1, 2, 3, 4, …. Boundaries on l: l = 0, 1, 2, 3, …, n-1 Boundaries on m l : m l = -l, . ., 0, …, +l Boundaries on m s : m s = +1/2, -1/2 (A) incorrect m s value (B) incorrect l value (C) correct (D) incorrect l value (E) incorrect m l value
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Name: ____________________ Student number: ______________ Page 6 of 26 Version # 1 Continued on next page 7. A beam of light with a frequency of 5.00 x 10 14 Hz ionizes a hydrogen atom that is already in an excited state (n = 4). The electron is ejected from the atom with a certain kinetic energy. What is the kinetic energy (in J) of the ejected electron? (A) 1.95 × 10 19 J (B) 1.36 × 10 19 J (C) 1.18 × 10 20 J (D) 3.26 × 10 5 J (E) 2.18 × 10 18 J 8. Select the statement that is FALSE regarding the perchlorate anion, ClO 4 , and the chlorate ion, ClO 3 , when they are drawn with charge minimized Lewis structures. (A) The formal charge of Cl in both ions is 0. (B) The oxidation state of Cl in ClO 3 +5. (C) The average Cl O bond length is longer in ClO 4 than in ClO 3 .
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RelativeResourceManager (2) - Name: _ Student number: _ See...

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