310 hw4 solution

# 310 hw4 solution - BUAD 310 Homework 4 Solutions Due...

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- 1 - BUAD 310 Homework 4 Solutions Due Tuesday, November 3, 2009 in class All problems with page numbers are from the textbook: 1. p. 511 #13.6 a. b 0 = 11.4641 b 1 = 24.6022 b 0 – 0 copiers, 11.46 minutes of service. b 1 – each additional copier adds 24.6022 minutes of service on average. No. The interpretation of b 0 does not make practical sense since it indicates that 11.46 minutes of service would be required for a customer with no copiers. b. y ˆ = 11.4641 + 24.6022(4) = 109.873 109.9 minutes 2. p. 516 #13.14 For problems 3 and 4 below you need to answer parts a through j (skip part k) given at the bottom of page 521 and at the top of page 522. 3. p. 522 #13.20 a. b 0 = 14.816 b 1 = 5.7066 b. SSE = 1.438 s 2 = .288 s = .5363 c. 1 b s = .3953 t = b 1 / 1 b s = 5.7066 /.3953 = 14.44 d. df = 5 t .025 = 2.571 Reject H 0 , strong evidence of a significant relationship between x and y. e.

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## 310 hw4 solution - BUAD 310 Homework 4 Solutions Due...

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