310 hw4 solution

310 hw4 solution - BUAD 310 Homework 4 Solutions Due...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
- 1 - BUAD 310 Homework 4 Solutions Due Tuesday, November 3, 2009 in class All problems with page numbers are from the textbook: 1. p. 511 #13.6 a. b 0 = 11.4641 b 1 = 24.6022 b 0 – 0 copiers, 11.46 minutes of service. b 1 – each additional copier adds 24.6022 minutes of service on average. No. The interpretation of b 0 does not make practical sense since it indicates that 11.46 minutes of service would be required for a customer with no copiers. b. y ˆ = 11.4641 + 24.6022(4) = 109.873 109.9 minutes 2. p. 516 #13.14 For problems 3 and 4 below you need to answer parts a through j (skip part k) given at the bottom of page 521 and at the top of page 522. 3. p. 522 #13.20 a. b 0 = 14.816 b 1 = 5.7066 b. SSE = 1.438 s 2 = .288 s = .5363 c. 1 b s = .3953 t = b 1 / 1 b s = 5.7066 /.3953 = 14.44 d. df = 5 t .025 = 2.571 Reject H 0 , strong evidence of a significant relationship between x and y. e.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Page1 / 3

310 hw4 solution - BUAD 310 Homework 4 Solutions Due...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online