WK5HW - JO - WK5HW JO Section 3.4 1. f(x) = x^2 3 12 y =...

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WK5HW – JO Section 3.4 1. f(x) = x^2 – 3 – 12 y = ax^2 + bx + c a = 1 b = -3 c = -12 a = 1 which is greater than 0, so the parabola would open upwards 3. h(x) = -3x^2 + 14x +1 y = ax^2 + bx + c a = -3 b = 14 c = 1 a = -3 which is less than 0, so the parabola would open downwards 6. h(x) = -4x^2 + 4.7x – 6 y = ax^2 + bx + c a = -4 b = 4.7 c = -16 a = -4 which is less than 0, so the parabola would open downwards 23. Vertex (-1,-2); point (1, 2) f(x) = a(x – h)^2 + k h =- 1 k = -2 f(x) = a(x + 1)^2 - 2 f(1) = 2 f(x) = a(x + 1)^2 -2 f(1) = a(1 + 1)^2 - 2 2 = a(2)^2 - 2
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4a = 4 a = 1 f(x) = (x + 1)^2 – 2 25. Vertex (0, 0); point (2, 12) f(x) = a(x – h)^2 + k h = 0 k = 0 f(x) = a(x -0)^2 +0 f(2) = 12 f(x) = a(x -0)^2 + 0 f(2) = a(2 – 0)^2 + 0 12 = a(2)^2 + 0 4a = 12 a = 3 f(x) = 3(x -0)^2 +0 f(x) = 3x^2 Section 3.5 1. C(x) = x^2 – 40x + 405 a) C(x) = 15^2 – 40(15) + 405 C(x) = 225 – 600 + 405 C(x) = 30 It costs $30 per box to make 15 boxes per day C(x) = 18^2 – 40(18) + 405 C(x) = 324 – 720 + 405
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This note was uploaded on 01/17/2010 for the course MATH 105 taught by Professor Dobra during the Spring '09 term at Upper Iowa.

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WK5HW - JO - WK5HW JO Section 3.4 1. f(x) = x^2 3 12 y =...

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