WK6HW – JO

WK6HW – JO - WK6HW JO Section 4.2 1. a)...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
WK6HW – JO Section 4.2 1. a) B(t) = 800(.9898^t) B(6) = 800(.9898^6) 752.27 The balance after 6 months would be $752.27 b) B(t) = 800(.9898^t) B(12) = 800(.9898^12) 707.39 The balance after 1 year would be $707.39 c) B(t) = 800(.9898^t) B(60) = 800(.9898^60) 432.45 The balance after 5 years would be $432.45 d) B(t) = 800(.9898^t) B(96) = 800(.9898^96) 298.98 The balance after 8 years would be $298.98 e) Don’t do it! You would never reach a zero balance! 3. f(t) = 4295.5e -.2294t (t 4) 2004 = 4 2006 = 6 2009 = 9 a) f(6) = 4295.5e -.2294(6) -.2294*6 = -1.3764 2.71828^-1.3764 .2524858
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
4295.5 * .2524858 1084.55 The average price of a LCD TV in 2006 would be about $1084.55 b) f(9) = 4295.5e -.2294(9) -.2294*9 = -2.0646 2.71828^-2.0646 .126869 4295.5 * .126869 544.97 The average price of a LCD TV in 2009 would be about $544.97 13. P(t) = 25 – 25e -3t a) P(1) = 25 – 25e -3(1) P(1) = about 6 items per day b) P(8) = 25 – 25e -3(8) P(8) = about 23 items per day c) The maximum number of items that could be produced would be 25
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 01/17/2010 for the course MATH 105 taught by Professor Dobra during the Spring '09 term at Upper Iowa.

Page1 / 7

WK6HW – JO - WK6HW JO Section 4.2 1. a)...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online