{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

WK7HW – JO

WK7HW – JO - r = 5/2(5/2-5/2 35 Multiply...

Info icon This preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
WK7HW – JO Section 6.1 3. 3x – y = 1 x + 2y = -9 y = 3x - 1 x + 2(3x - 1) = -9 x - 2 + 6x = -9 7x - 2 = -9 -9 + 2 7x = -7 7/-7 = -1 x = -1 3(-1) – y = 1 -3 – y = 1 -3 – 1 = -4 y = -4 (-1, -4) 5. 3x – 2y = 4 2x + y = -1 y = -1 – 2x 3x – 2(-1 – 2x) = 4 3x + 2 + 4x = 4 7x + 2 = 4
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
7x = 2 x = 2/7 y = -1 – 2(2/7) y = -1 – 4/7 y = - 11/7 (2/7, -11/7) 7 .  r + s = 0 r – s = 5 r = 0 – s 0 – s – s = 5 0 – 2s = 5 -2s = 5 s = -5/2 r + (– 5/2) = 0
Image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: r = 5/2 (5/2, -5/2) 35. Multiply the second equation by -1 3x + z + 2w +18v = 0-4x + y - w - 24v = 0 7x – y + z + 3w + 42v = 0 4x + z + 2w + 24v = 0 37. Replace the second equation by the sum of itself and -2 times the first equation x + y + 2z + 3w = 1 -y - 1z - 2w = -1 3x + y + 4z + 5w = 2 2x + y + 3z + 4w = 1 x + y + 2z + 3w = 1-2x – 2y - 4z -6w = -2-y - 1z – 2w = -1...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern