WK3DQ – JO

WK3DQ – JO - (220*0.85)-0.85x+(48*0.85) =...

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WK3DQ – JO a. y = (220-x) *(.65) y = (220-x) *(.85) x = age b. y = (220-20) *(.65) y = 130 y = (220-20) * (.85) y = 170 c. y = (220-40) * (.65) y = 117 y = (220-40) * (.85) y = 153 d. (220-(x+48)*.85 = (220-x)*0.65
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Unformatted text preview: (220*0.85)-0.85x+(48*0.85) = 143-0.65x 187-0.85x-40.80=143-0.65x-0.85x+146.20 = 143-0.65x-0.85x+0.65x = 143 146.20 -0.20x = - 3.20 x = (3.20/0.20) x = 16 Age of younger Woman = 16 Age of Older Woman = 16+48 = 64 y = (220-16)* (.65) y = 132.6 y = (220-64)* (.85) y = 132.6 The pulse of both women is 132.6...
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This note was uploaded on 01/17/2010 for the course MATH 105 taught by Professor Dobra during the Spring '09 term at Upper Iowa.

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WK3DQ – JO - (220*0.85)-0.85x+(48*0.85) =...

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