example_MPt - 60 80 100 120 4 8 12 16 20 24 X 0.001)...

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Stat 2225 Handout Example in Matched-Pair t-test Q12.75 on p.425. Consider the two variables (or samples) are independent: Summary Statistics New Existing ------------------------------------------------------------ Count 20 20 Average 73.6 69.05 Variance 242.779 316.366 Standard deviation 15.5814 17.7867 ------------------------------------------------------------ Comparison of Means ------------------- 95.0% confidence interval for the difference between the means assuming equal variances: 4.55 +/- 10.7039 [-6.15393,15.2539] t test to compare means Null hypothesis: mean1 = mean2 Alt. hypothesis: mean1 > mean2 assuming equal variances: t = 0.860527 P-value = 0.197448 New Existing frequency 40 60 80 100 120 7 4 1 2 5 8 Variabl New Existin Density Traces 40
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Unformatted text preview: 60 80 100 120 4 8 12 16 20 24 X 0.001) density Page 1 of 2 Consider they are matched: Summary Statistics for New-Existing Count = 20 Average = 4.55 Variance = 52.1553 Standard deviation = 7.22186 Confidence Intervals for New-Existing ------------------------------------- 95.0% confidence interval for mean: 4.55 +/- 3.37994 [1.17006,7.92994] Hypothesis Tests for New-Existing Sample mean = 4.55 t-test ------ Null hypothesis: mean = 0.0 Alternative: greater than Computed t statistic = 2.81759 P-Value = 0.00549709 Reject the null hypothesis for alpha = 0.05. Histogram New-Existing frequency-15 -10 -5 5 10 15 1 2 3 4 5 6 Density Trace New-Existing density-15 -10 -5 5 10 15 0.01 0.02 0.03 0.04 0.05 0.06 Page 2 of 2...
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example_MPt - 60 80 100 120 4 8 12 16 20 24 X 0.001)...

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