example_2t - assuming equal variances: t = -4.1382 P-value...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Stat 2225 Handout Inference for Two Independent Populations Q13.39 on p.410 Summary Statistics Drug Exercise ------------------------------------------------------------ Count 25 25 Average 9.92 13.52 Variance 13.16 5.76 Standard deviation 3.62767 2.4 Minimum 4.0 7.0 Maximum 16.0 19.0 ------------------------------------------------------------ Comparison of Means ------------------- 95.0% confidence interval for mean of Drug: 9.92 +/- 1.49743 [8.42257,11.4174] 95.0% confidence interval for mean of Exercise: 13.52 +/- 0.990673 [12.5293,14.5107] 95.0% confidence interval for the difference between the means assuming equal variances: -3.6 +/- 1.74914 [-5.34914,-1.85086] t test to compare means Null hypothesis: mean1 = mean2 Alt. hypothesis: mean1 NE mean2
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: assuming equal variances: t = -4.1382 P-value = 0.000140376 Comparison of Means ------------------- 95.0% confidence interval for mean of Drug: 9.92 +/- 1.49743 [8.42257,11.4174] 95.0% confidence interval for mean of Exercise: 13.52 +/- 0.990673 [12.5293,14.5107] 95.0% confidence interval for the difference between the means not assuming equal variances: -3.6 +/- 1.75608 [-5.35608,-1.84392] t test to compare means Null hypothesis: mean1 = mean2 Alt. hypothesis: mean1 NE mean2 not assuming equal variances: t = -4.1382 P-value = 0.00016653 Histogram and Density Trace: Drug Exercise frequency 4 8 12 16 20 10 6 2 2 6 10 Variable Drug Exerci Density Traces 4 8 12 16 20 0.03 0.06 0.09 0.12 0.15 density...
View Full Document

Ask a homework question - tutors are online