{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Exam1solutions

# Exam1solutions - m z = M d x-3 L 4 ˆ ˜ Therefore GDE...

This preview shows page 1. Sign up to view the full content.

1 AE 221 – Spring 2004 – EXAM #1 Solutions 1. The is an extension and a bending problem in this case. Since the beam is of homogeneous and symmetric cross-section I yz = 0, thus uncoupling the y and z bending problems. Extension: GDE: EA ¢ u ( ) ¢ = - f x = 0 BCs: u 0 ( ) = 0 EA ¢ u L ( ) = P Bending: GDE: EA ¢ ¢ v ( ) ¢¢ = f y - ¢ m z Here f y = - 2 P 0 L x L stp L 2 - x -
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: m z = M d x-3 L 4 ˆ ˜ Therefore GDE becomes: EA ¢ ¢ v ( ) ¢¢ = -2 P L x L ˆ ˜ -gA-M ¢ d x-3 L 4 ˆ ˜ BCs: EI ¢ ¢ v ( ) = -M v L ( ) = EI ¢ ¢ ¢ v ( ) = -kv ( ) EI ¢ ¢ v L ( ) = -K ¢ v L ( ) 2. This is the same problem as question 0(f) in Chapter 2.1....
View Full Document

{[ snackBarMessage ]}

### What students are saying

• As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

Kiran Temple University Fox School of Business ‘17, Course Hero Intern

• I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

Dana University of Pennsylvania ‘17, Course Hero Intern

• The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

Jill Tulane University ‘16, Course Hero Intern