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Unformatted text preview: quadratic takes the following form: (1) 2 = + + c bQ aQ then you can use the following formula to uncover the roots or the Q values that allow the equation to equal zero. (2) a ac b b Q Q 2 4 , 2 2 1 = Looking at equation (#) in this case, we find that a = 1, b = -90, and c = 1800 and, therefore, 1 Q =30 and 2 Q = 60. The next step is to solve for P. We can find this by substituting both values of Q into one of the original equations. For Q = 30, P = 70 and for Q = 60, P = 40. Note that both sets of prices (P) and quantities (Q) are positive. These two solutions correspond to the intersections on the graph below. P Q 70 100 100 30 40 60 P = 1800/Q + 10 P =100 - Q...
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- Spring '06