Momentum and Collisions.pdf - NAME _ DATE _ CLASS _...

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Problem DCh. 6–7NAME ______________________________________ DATE _______________ CLASS ____________________Momentum and CollisionsProblem DCONSERVATION OF MOMENTUMP R O B L E MA 20.0 kg cannonball is fired from a 2.40×103kg. If the cannonrecoils with a velocity of 3.5 m/s backwards, what is the velocity of thecannonball?S O L U T I O NGiven:m1=mass of cannonball=20.0 kgm2=mass of cannon=2.40×103kgv1,i=initial velocity of cannonball=0 m/sv2, i=initial velocity of cannon=0 m/sv2,f=final velocity of cannon=3.5 m/s backwards= −3.5 m/sUnknown:v1, f=final mass of cannonball=?Choose the equation(s) or situation:Because the momentum of the cannon-cannonball system is conserved and therefore remains constant, the total initialmomentum of the cannon and cannonball will equal the total final momentumof the cannon and cannonball.m1v1,i+m2v2,i=m1v1,f+m2v2,fBecause the cannon and cannonball are initially at rest, the initial momentum foreach is zero. From momentum conservation it follows that the total final mo-mentum is also zero.m1v1,f+m2v2,f=0Rearrange the equation(s) and isolate the unknown(s):v1,f=mm21v2,fSubstitute the values into the equation(s) and solve:v1,f==420 m/sv1,f=

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Term
Fall
Professor
Mr. Coleman
Tags
Momentum, Holt, V1

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