Chapter 25 Solutions

Chapter 25 Solutions - Chapter 25 Solutions indicates a...

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Chapter 25 Solutions (* indicates a graded problem) 25.1. Model: Use the charge model. Solve: (a) In the process of charging by rubbing, electrons are removed from one material and transferred to the other because they are relatively free to move. Protons, on the other hand, are tightly bound in nuclei. So, electrons have been removed from the glass rod to make it positively charged. (b) Because each electron has a charge of 19 1.60 10 C ! " , the number of electrons removed is 9 10 19 5 10 C 3.13 10 1.60 10 C ! ! " = " " 25.7. Model: Use the charge model and the model of a conductor as a material through which electrons move. Solve: The first step shows two neutral metal spheres touching each other. In the second step, the negative rod repels the negative charges which will retreat as far as possible from the top of the left sphere. Note that the two spheres are touching and the net charge on these two spheres is still zero. While the rod is there on top of the left sphere, the right sphere is moved away from the left sphere. Because the right sphere has an excess negative charge by the same amount as the left sphere has an excess positive charge, the separated right sphere is negatively charged as shown in the third step. As the two spheres are moved apart further and the negatively charged rod is moved away from the spheres, the charges on the two spheres redistribute uniformly over the entire sphere surface. Thus, we have oppositely charged the two spheres. 25.14. Model: Charges A, B, and C are point charges.
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