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Unformatted text preview: t 1 2245 0, t 2 2245 1, t 3 << 1. Hence, k t 3 tot = 3 Since electrons are the major electronic defect, the main contribution to 3 is by electrons. Therefore, in order to reduce the rate of fluoridation, we have to reduce the electron concentration in CaF 2 . For this purpose, we may dope lower valence cations, for example, NaF. The doping reaction equation is given by NaF Na Ca ' + V F + F F From the equilibrium constants, K 1 , K 2 and K 3 , we can see that NaF doping results in V F [ ] F i ' [ ] h [ ] e ' [ ]...
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- Spring '02