Serway_PSE_quick_ch24

# Serway_PSE_quick_ch24 - Physics for Scientists and...

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Physics for Scientists and Engineers, 6e Chapter 24 – Gauss’s Law

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Suppose the radius of the sphere in Example 24.1 (radius 1.00 m, with a charge of +1.00 μ C at its center) is changed to 0.500 m. What happens to the flux through the sphere and the magnitude of the electric field at the surface of the sphere? 1 2 3 4 5 6 17% 17% 17% 17% 17% 17% 1 2 3 4 5 1. The flux and field both increase. 2. The flux and field both decrease. 3. The flux increases and the field decreases. 4. The flux decreases and the field increases. 5. The flux remains the same and the field increases. 6. The flux decreases and the field remains the same.
The same number of field lines pass through a sphere of any size. Because points on the surface of the sphere are closer to the charge, the field is stronger.

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In a charge-free region of space, a closed container is placed in an electric field. A requirement for the total electric flux through the surface of the container to be zero is that 1 2 3 4 25% 25% 25% 25% 1 2 3 4 5 1. the field must be uniform 2.
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• Spring '08
• Davies
• Charge, Electric charge, Surface, total electric flux

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