Serway_PSE_quick_ch30

Serway_PSE_quick_ch30 - Physics for Scientists and...

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Physics for Scientists and Engineers, 6e Chapter 30 – Sources of the Magnetic Field
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Consider the current in the length of wire shown in the figure below. Rank the points A , B , and C , in terms of magnitude of the magnetic field due to the current in the length element shown, from greatest to least. 1 2 3 4 5 20% 20% 20% 20% 20% 1 2 3 4 5 1. A, B, C 2. B, C, A 3. C, B, A 4. C, A, B 5. An equal field applies at all these points.
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Point B is closest to the current element. Point C is farther away and the field is further reduced by the sin θ factor in the cross product d s × . The field at A is zero because θ = 0.
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For I 1 = 2 A and I 2 = 6 A in the figure below, which is true: 1 2 3 33% 33% 33% 1 2 3 4 5 1. F 1 = 3 F 2 2. F 1 = F 2 /3 3. F 1 = F 2
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F 1 = F 2 as required by Newton’s third law. Another way to arrive at this answer is to realize that Equation 30.11 gives the same result whether the multiplication of currents is (2 A)(6 A) or (6 A)(2 A).
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A loose spiral spring is hung from the ceiling, and a large current is sent through it. The coils move 1 2 3 33% 33% 33% 1 2 3 4 5 1. closer together 2. farther apart 3. they do not move at all
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The coils act like wires carrying parallel currents in the same direction and hence attract one another.
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This note was uploaded on 01/19/2010 for the course PHYS 200 taught by Professor Davies during the Spring '08 term at Roger Williams.

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Serway_PSE_quick_ch30 - Physics for Scientists and...

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