M408L_HW04 - hyun (hh7953) HW04 gogolev (57440) 1 This...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: hyun (hh7953) HW04 gogolev (57440) 1 This print-out should have 22 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 4) 10.0 points A Calculus student begins walking in a straight line from the RLM building towards the PCL Library. After t minutes his velocity v = v ( t ) is given (in multiples of 10 yards per minute) by the function whose graph is 2 4 6 8 10- 2 2 4 6- 2 t v How far is the student from the RLM build- ing at time t = 4? 1. dist = 160 yards 2. dist = 130 yards 3. dist = 140 yards correct 4. dist = 150 yards 5. dist = 180 yards Explanation: The student is walking towards the PCL Library whenever v ( t ) > 0 and towards RLM whenever v ( t ) < 0. The distance he has walked is given by 10 times the area between the graph of v and the t axis since 1 unit is equivalent to 10 yards. Now at t = 4 this area is 14 units, so the student has walked a distance of 140 yards. 002 (part 2 of 4) 10.0 points How far is the student from the RLM build- ing at time t = 6? 1. dist = 240 yards 2. dist = 230 yards correct 3. dist = 250 yards 4. dist = 270 yards 5. dist = 220 yards Explanation: The distance the student has walked is given by the area between the graph of v and the t axis. Now at t = 6 this area is 23 units, so the student has walked a distance of 230 yards. 003 (part 3 of 4) 10.0 points What is the total distance walked by the student from time t = 0 to t = 10? 1. dist = 290 yards correct 2. dist = 300 yards 3. dist = 280 yards 4. dist = 270 yards 5. dist = 320 yards Explanation: The distance the student has walked is given by the area between the graph of v and the t axis. Now at t = 10 this area is 29 units (area is always positive remember), so the student has walked a distance of 290 yards. 004 (part 4 of 4) 10.0 points How far is the student from the RLM build- ing when he turns back? 1. dist = 250 yards 2. dist = 280 yards hyun (hh7953) HW04 gogolev (57440) 2 3. dist = 230 yards 4. dist = 260 yards correct 5. dist = 300 yards Explanation: The student will turn back when his veloc- ity changes from postive to negative, i.e. , at t = 7. At this time he is 260 yards from the RLM building. keywords: distance, time, graph, velocity, area 005 10.0 points The graph of f is shown in the figure 2 4 6 8 2 4 6 If F is an anti-derivative of f and integraldisplay 8 3 f ( x ) dx = 23 , find the value of F (8)- F (2). 1. F (8)- F (2) = 29 2. F (8)- F (2) = 28 correct 3. F (8)- F (2) = 32 4. F (8)- F (2) = 31 5. F (8)- F (2) = 30 Explanation: We already know that the area under the graph on the interval 3 x 8 is equal to 23, alternatively, by the Fundamental Theorem of Calculus we can say that F (8)- F (3) = 23 ....
View Full Document

Page1 / 9

M408L_HW04 - hyun (hh7953) HW04 gogolev (57440) 1 This...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online