# ASM2 - The problem is that n1 n2 n3 are integers of int...

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Can’t get the correct answer for the average of three input numbers from your program? Let’s look at the body of the Average3.java program listed below: System.out.println("Programming Assignment # 2"); System.out.println("\n"); System.out.println("Average of Three Integers"); System.out.println("\n"); System.out.println("Please enter three whole numbers on a line:"); int n1, n2, n3; Scanner keyboard = new Scanner(System.in); n1 = keyboard.nextInt(); n2 = keyboard.nextInt(); n3 = keyboard.nextInt(); System.out.println("\n"); System.out.println("The average of the three numbers is"); System.out.println((n1 + n2 + n3) / 3); System.out.println("\n"); The answer from this program will not be as accurate as it should be.
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Unformatted text preview: The problem is that n1, n2, n3 are integers of int type, and 3 is also an integer. Your answer will be stored as an integer with decimal digits truncated. Try the following methods to correct this problem: a. Typecast the total you summed : System.out.println( (double) (n1 + n2 + n3) / 3); b. System.out.println( (n1 + n2 + n3) / 3 . ); // notice the period after the 3. Why does this work? c. Try to create a variable to hold the sum and a double type variable to hold the average of the three numbers: a. double sum = n1 + n2 + n3; b. double ave = sum / 3; d. Will the following statement produce accurate answer to the 2 nd decimal digit? double ave = (n1 + n2 + n3) / 3;...
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## This note was uploaded on 01/20/2010 for the course MATH 107 taught by Professor Christinashow during the Spring '08 term at Mesa CC.

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