# 20 - Shie Gary – Homework 20 – Due 4:00 am – Inst...

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Unformatted text preview: Shie, Gary – Homework 20 – Due: Oct 20 2004, 4:00 am – Inst: Turner 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. The due time is Central time. 001 (part 1 of 1) 10 points A coil is wrapped with 165 turns of wire on the perimeter of a square frame of sides 29 . 8 cm. Each turn has the same area, equal to that of the frame, and the total resistance of the coil is 4 . 62 Ω. A uniform magnetic field is turned on perpendicular to the plane of the coil. If the field changes linearly from 0 to- . 0886 Wb / m 2 in a time of 1 . 08 s, find the magnitude of the induced emf in the coil while the field is changing. Correct answer: 1 . 20206 V. Explanation: Basic Concept: Faraday’s Law is E =- d Φ B dt . Solution: The magnetic flux through the loop at t = 0 is zero since B = 0. At t = 1 . 08 s , the magnetic flux through the loop is Φ B = B A =- . 00786803 Wb . Therefore the magnitude of the induced emf is E = N · ΔΦ B Δ t = (165 turns)[(- . 00786803 Wb)- 0] (1 . 08 s) =- 1 . 20206 V |E| = 1 . 20206 V . 002 (part 1 of 1) 10 points A constant current is flowing through a solenoid, creating a magnetic field. V I B conducting ring The force which the magnetic field exerts on a conducting ring positioned as shown is: 1. upward 2. There is neither a force nor a torque. correct 3. There is no force, only a torque. 4. downward Explanation: The magnetic field within the conducting ring is constant since the current flowing through the solenoid is constant in time. In other words, there is no induced current in the conducting ring. Therefore, no force nor torque is exerted on the conducting ring. 003 (part 1 of 1) 10 points A flexible loop of conducting wire has a radius of 11 cm and is in a magnetic field of strength of 0 . 27 T....
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20 - Shie Gary – Homework 20 – Due 4:00 am – Inst...

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