HW_S09_08 - .OP .TRAN 1U 5M .FOUR 1KHZ V(7) .MODEL NBJT NPN...

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14.107 *Problem 14.107 - Multistage Amplifier – Figure P14.106 VCC 12 0 DC 15 VI 1 0 AC 1 RI 1 2 10K *For output resistance *VI 1 0 AC 0 *VO 11 0 AC 1 C1 2 3 22U R1 12 3 820K R2 3 0 100K Q1 5 3 4 NBJT RE1 4 0 2K C2 4 0 22U RC1 12 5 18K C3 5 6 22U R3 12 6 160K R4 6 0 43K Q2 8 6 7 NBJT RC 12 8 4.7K RE2 7 0 1.6K C4 7 0 22U C5 8 9 22U R5 12 9 910K R6 9 0 1.2MEG M3 12 9 10 10 NMOSFET
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RE3 10 0 3K C6 10 11 22U RL 11 0 250 .OP .AC LIN 1 3KHZ 3KHZ .MODEL NMOSFET NMOS VTO=1 KP=.001 LAMBDA=0.02 .MODEL NBJT NPN IS=1E-16 BF=100 VA=70 .PRINT AC VM(3) VP(3) IM(VI) IP(VI) VM(11) VP(11) IM(C6) IP(C6) .END Results: A v = VM (11) = + 711 | R in = VM (3) IM ( VI ) = 8.29 k | R out = 1 IM ( C 6) = 401
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14.55 *Problem 14.55 - Common-Emitter Amplifier 5mV VCC 6 0 DC 9 VEE 4 0 DC -9 VS 1 0 SIN(0 0.005 1K) C1 1 2 1U RB 2 0 10K RC 6 5 3.6K RE 3 4 2K C2 3 0 50U C3 5 7 1U R3 7 0 10K Q1 5 2 3 NBJT
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Unformatted text preview: .OP .TRAN 1U 5M .FOUR 1KHZ V(7) .MODEL NBJT NPN IS=1E-16 BF=100 VA=70 .PROBE V(7) .END *Problem 14.55 - Common-Emitter Amplifier 10mV VCC 6 0 DC 9 VEE 4 0 DC -9 VS 1 0 SIN(0 0.01 1K) C1 1 2 1U RB 2 0 10K RC 6 5 3.6K RE 3 4 2K C2 3 0 50U C3 5 7 1U R3 7 0 10K Q1 5 2 3 NBJT .OP .TRAN 1U 5M .FOUR 1KHZ V(7) .MODEL NBJT NPN IS=1E-16 BF=100 VA=70 .PROBE V(7) .END *Problem 14.55 - Common-Emitter Amplifier 15mV VCC 6 0 DC 9 VEE 4 0 DC -9 VS 1 0 SIN(0 0.015 1K) C1 1 2 1U RB 2 0 10K RC 6 5 3.6K RE 3 4 2K C2 3 0 50U C3 5 7 1U R3 7 0 10K Q1 5 2 3 NBJT .OP .TRAN 1U 5M .FOUR 1KHZ V(7) .MODEL NBJT NPN IS=1E-16 BF=100 VA=70 .PROBE V(7) .END Results: v i 1 kHz 2 kHz 3 kHz THD 5 mV 5.8 mV 0.335 mV (5.7%) 0.043 mV (0.74% 5.9% 10 mV 12.4 mV 1.54 mV (12.5%) 0.258 mV (2.1%) 12.8% 15 mV 20.6 mV 4.32 mV (21%) 1.18 mV (5.4%) 22%...
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This note was uploaded on 01/20/2010 for the course ECE 255 taught by Professor Staff during the Spring '08 term at Purdue University-West Lafayette.

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HW_S09_08 - .OP .TRAN 1U 5M .FOUR 1KHZ V(7) .MODEL NBJT NPN...

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