HW_S09_09 - 14.109 Note that the equivalent circuits are...

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Unformatted text preview: 14.109 Note that the equivalent circuits are the same for Q 1 and Q 2 . V EQ = 180 k Ω 180 k Ω + 300 k Ω 15 V = 5.63 V | R EQ = 180 k Ω 300 k Ω = 113 k Ω I B = 5.63- 0.7 113 + 101 20 ( 29 V k Ω = 2.31 μ A | I C = 100 I B 1 = 232 μ A | I E = 101 I B 1 = 234 μ A V CE = 15- 2 x 10 4 I E- 2 x 10 4 I C = 5.71 V r π = 100 0.025 V ( 29 232 μ A = 10.8 k Ω | r o = 70 + 5.71 ( 29 V 232 μ A = 326 k Ω A v = R in 2 k Ω + R in A vt 1 A vt 2 A vt 1 = v 2 v 1 = - β o 1 R I 1 r π 2 ( 29 r π 1 + β o 1 + 1 ( 29 R 5 = - 100 17 k Ω 10.8 k Ω ( 29 10.8 k Ω + 101 ( 29 2 k Ω = - 3.10 A vt 2 = v o v 2 = - g m 2 R L | R L = 100 k Ω 20 k Ω = 16.7 k Ω | A vt 2 = - 40 232 μ A ( 29 16.7 k Ω ( 29 = - 155 R in = R B 1 r π 1 + β o 1 + 1 ( 29 R 5 ( 29 = 300 k Ω 180 k Ω 10.8 k Ω + 101 ( 29 2 k Ω [ ] = 73.6 k Ω A v = 73.6 k Ω 2 k Ω + 73.6 k Ω - 3.10 ( 29- 155 ( 29 = + 468 | R out = 20 k Ω r o 2 = 20 k Ω 326 k...
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This note was uploaded on 01/20/2010 for the course ECE 255 taught by Professor Staff during the Spring '08 term at Purdue University.

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HW_S09_09 - 14.109 Note that the equivalent circuits are...

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