Sol2 - ECE 255 ELECTRONIC ANALYSIS AND DESIGN Fall 2009...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: ECE 255 ELECTRONIC ANALYSIS AND DESIGN Fall 2009 Homework 2 Solutions Problem 1 (Text 3.71) Find the Q-points for the diodes in the four circuits shown using: (a) The ideal diode model (a) Both diodes are forward biased [ ] D2 ( 9) V I 409 A 22 k- - = = D1 (6 0) V I 409 A 270 A 43k- = - = Q D1 : {V D1 = 0, I D1 = 270 A} and Q D2 : {V D2 = 0, I D2 = 409 A} (b) Diode D 1 is forward biased and diode D 2 is reverse biased D1 (6 0) V I 140 A 43k- = = and V D2 = 9 V Q D1 : {V D1 = 0, I D1 = 140 A} and Q D2 : {V D2 = 9 V, I D2 = 0} (c) Diode D 1 is reverse biased and diode D 2 is forward biased [ ] D2 6 ( 9) V I 231 A 65k- - = = and D1 D2 V = 6 V 43k I 3.92 V- = - Q D1 : {V D1 = 3.92 V, I D1 = 0} and Q D2 : {V D2 = 0, I D2 = 231 A} (d) Both diodes are forward biased [ ] D2 ( 6) V I 140 A 43k- - = = D1 (9 0) V I 140 A 270 A 22 k- =- = Q D1 : {V D1 = 0, I D1 = 270 A} and Q D2 : {V D2 = 0, I D2 = 140 A} (b) The constant voltage drop model with V on = .75 V (a) Both diodes are forward biased [ ] D2 .75 .75 ( 9) V I 341 A 22 k--- - = = D1 6 ( .75) V I 341 A 184 A 43k- - = - = Q D1 : {V D1 = .75 V, I D1 = 184 A} and Q D2 : {V D2 = .75 V, I D2 = 341 A} (b) Diode D 1 is forward biased and diode D 2 is reverse biased D1 (6 .75) V I 122 A 43k- = = and V D2 = 9 .75 = 9.75 V Q D1 : {V D1 = .75 V, I D1 = 122 A} and Q D2 : {V D2 = 9.75 V, I D2 = 0} (c) Diode D 1 is reverse biased and diode D 2 is forward biased [ ] D2 6 .75 ( 9) V I 219 A 65k-- - = = and D1 D2 V = 6 V 43k I 3.43V- = - Q D1 : {V D1 = 3.43 V, I D1 = 0} and Q D2 : {V D2 = .75 V, I D2 = 219 A} (d) Both diodes are forward biased [ ] D2 .75 .75 ( 6) V I 140 A 43k-- - = = D1 (9 .75) V I 140 A 235 A 22 k- =- = Q D1 : {V D1 = .75 V, I D1 = 235 A} and Q D2 : {V D2 = .75 V, I D2 = 140 A} Problem 2 (Text 3.71 cont.) (c) A diode model containing an ideal diode, a voltage source, V = .65 V, and resistor, R = 200 . (a) Assume both diodes are forward biased Define the voltage at the junction of the two diodes as V X mV 688 V 200 k 22 ) V 9 ( V 65 . V 200 V 65 . V k 43 V V 6 X X X X- = + --- + + = - A 190 200 V V 65 ....
View Full Document

Page1 / 7

Sol2 - ECE 255 ELECTRONIC ANALYSIS AND DESIGN Fall 2009...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online