# Sol2 - ECE 255 ELECTRONIC ANALYSIS AND DESIGN Fall 2009...

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Unformatted text preview: ECE 255 ELECTRONIC ANALYSIS AND DESIGN Fall 2009 Homework 2 Solutions Problem 1 (Text 3.71) Find the Q-points for the diodes in the four circuits shown using: (a) The ideal diode model (a) Both diodes are forward biased [ ] D2 ( 9) V I 409 A 22 k- - = = D1 (6 0) V I 409 A 270 A 43k- = - = Q D1 : {V D1 = 0, I D1 = 270 A} and Q D2 : {V D2 = 0, I D2 = 409 A} (b) Diode D 1 is forward biased and diode D 2 is reverse biased D1 (6 0) V I 140 A 43k- = = and V D2 = 9 V Q D1 : {V D1 = 0, I D1 = 140 A} and Q D2 : {V D2 = 9 V, I D2 = 0} (c) Diode D 1 is reverse biased and diode D 2 is forward biased [ ] D2 6 ( 9) V I 231 A 65k- - = = and D1 D2 V = 6 V 43k I 3.92 V- = - Q D1 : {V D1 = 3.92 V, I D1 = 0} and Q D2 : {V D2 = 0, I D2 = 231 A} (d) Both diodes are forward biased [ ] D2 ( 6) V I 140 A 43k- - = = D1 (9 0) V I 140 A 270 A 22 k- =- = Q D1 : {V D1 = 0, I D1 = 270 A} and Q D2 : {V D2 = 0, I D2 = 140 A} (b) The constant voltage drop model with V on = .75 V (a) Both diodes are forward biased [ ] D2 .75 .75 ( 9) V I 341 A 22 k--- - = = D1 6 ( .75) V I 341 A 184 A 43k- - = - = Q D1 : {V D1 = .75 V, I D1 = 184 A} and Q D2 : {V D2 = .75 V, I D2 = 341 A} (b) Diode D 1 is forward biased and diode D 2 is reverse biased D1 (6 .75) V I 122 A 43k- = = and V D2 = 9 .75 = 9.75 V Q D1 : {V D1 = .75 V, I D1 = 122 A} and Q D2 : {V D2 = 9.75 V, I D2 = 0} (c) Diode D 1 is reverse biased and diode D 2 is forward biased [ ] D2 6 .75 ( 9) V I 219 A 65k-- - = = and D1 D2 V = 6 V 43k I 3.43V- = - Q D1 : {V D1 = 3.43 V, I D1 = 0} and Q D2 : {V D2 = .75 V, I D2 = 219 A} (d) Both diodes are forward biased [ ] D2 .75 .75 ( 6) V I 140 A 43k-- - = = D1 (9 .75) V I 140 A 235 A 22 k- =- = Q D1 : {V D1 = .75 V, I D1 = 235 A} and Q D2 : {V D2 = .75 V, I D2 = 140 A} Problem 2 (Text 3.71 cont.) (c) A diode model containing an ideal diode, a voltage source, V = .65 V, and resistor, R = 200 . (a) Assume both diodes are forward biased Define the voltage at the junction of the two diodes as V X mV 688 V 200 k 22 ) V 9 ( V 65 . V 200 V 65 . V k 43 V V 6 X X X X- = + --- + + = - A 190 200 V V 65 ....
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## Sol2 - ECE 255 ELECTRONIC ANALYSIS AND DESIGN Fall 2009...

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