# 11 - EE 2001 Fall 2008 Problem Set 11 Solution The op-amp...

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EE 2001 Fall 2008 Problem Set 11 Solution ______________________________________________________________________ The op-amp below is not ideal; its gain is not infinite, its gain is not constant, and its gain is not even linear. Solve this circuit for v o using load line techniques. Load Line Analysis: v o and v pn are related to each other in two ways. First, by the gain profile that is shown. Second, by the voltage divider comprised of the 10k and 90k resistors. Express v o as a function of v pn as determined by the voltage divider. Sketch this relationship on the graph to find v o . Solution: v o = 10*v n [voltage divider] v n = 1- v pn so, v o = 10 – 10*v pn v o (v pn = 8 mV) = 9.92 V v o (v pn = 10 mV) = 9.9 V The curves intersect at vo = 9.915 V + 1 V _ R L v O 90 k 10 k v O v pn (mV) 10.00 9.95 9.90 10 9 8 v n v p

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We can also solve this circuit by using the process of iteration. This is a series of guesses, each guess suggesting a subsequent guess that is usually better. Note:
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11 - EE 2001 Fall 2008 Problem Set 11 Solution The op-amp...

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