# oldhw 41 - nguyen(jmn727 oldhomework 40 Turner(59070 This...

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nguyen (jmn727) – oldhomework 40 – Turner – (59070) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page – fnd all choices beFore answering. 001 (part 1 oF 3) 10.0 points A standard setup oF the double slit experiment as shown in the sketch. The distance between the two slits is d , the wave length oF the incident wave is λ , the distance between the slits and the screen is L . A point on the screen is specifed by its y-coordinate, or the corresponding angle θ . y L d S 1 S 2 θ viewing screen θ δ At the Fourth minimum on the screen what is φ (the phase angle di±erence oF the two rays From slit S 1 and slit S 2 ) and δ (the corre- sponding path di±erence)? 1. φ = 7 π and δ = 7 λ 2. φ = 6 π and δ = 6 λ 3. φ = 4 π and δ = 2 λ 4. φ = 5 π and δ = 5 λ 5. φ = 5 π and δ = 5 2 λ 6. φ = 8 π and δ = 4 λ 7. φ = 6 π and δ = 3 λ 8. φ = 7 π and δ = 7 2 λ correct 9. φ = 8 π and δ = 8 λ 10. φ = 4 π and δ = 4 λ Explanation: In general, the phase angle di±erence For minima is given by φ = (2 n + 1) π, with n = 0 , 1 , 2 ··· . The Fourth minimum corresponds to n = 3, so φ = 7 π and δ = p λ 2 π P φ = λ 2 π (7 π ) = 7 2 λ . 002 (part 2 oF 3) 10.0 points What is the vertical distance y For the frst maximum (which is adjacent to the central maximum)? Use the small angle approxima- tion. 1. y = 2 λ L d 2. y = λ d 2 L 3. y = 2 λ d L 4. y = λ L 2 d 5. y = d L λ 6. y = d L 2 λ 7. y = λ L d correct 8. y = λ 9. y = λ d L 10. y = 2 d L λ Explanation: The frst maximum occurs when the path di±erence is λ , so θ = λ d = y L y = λ L d . 003 (part 3 oF 3) 10.0 points ²ind the minimum positive θ value such that

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nguyen (jmn727) – oldhomework 40 – Turner – (59070) 2 I I 0 = 1 4 , where I 0 and I are the intensities of light at 0 and at θ , respectively. Use the small angle approximation.
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oldhw 41 - nguyen(jmn727 oldhomework 40 Turner(59070 This...

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