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Unformatted text preview: nguyen (jmn727) homework 26 Turner (59070) 1 This printout should have 11 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A solenoid has 129 turns of wire uniformly wrapped around an airfilled core, which has a diameter of 8 mm and a length of 4 . 4 cm. The permeability of free space is 1 . 25664 10 6 N / A 2 . Calculate the selfinductance of the solenoid. Correct answer: 2 . 38895 10 5 H. Explanation: Let : N = 129 , D = 8 mm = 0 . 008 m , = 4 . 4 cm = 0 . 044 m , and = 1 . 25664 10 6 N / A 2 . The selfinductance of a solenoid is given by L 1 = N I , where is the total flux inside the solenoid and I is the current in the wire wrapped around the solenoid. By Amperes Law, the magnetic field in the solenoid is B = N I , where = is the magnetic permeability of the air core which is the same as free space. The magnetic flux in the solenoid is = B A = B D 2 4 . Using the above expressions for and B , we obtain for the inductance of the solenoid L 1 = N B A I = N 2 D 2 4 = (1 . 25664 10 6 N / A 2 ) (129) 2 (0 . 008 m) 2 4 (0 . 044 m) = 2 . 38895 10 5 H . 002 (part 2 of 2) 10.0 points The core is replaced with a soft iron rod that has the same dimensions, but a magnetic per meability of 800 . What is the new inductance? Correct answer: 0 . 0191116 H. Explanation: Let : = 800 . L 2 = N 2 D 2 4 = L 1 = 800(2 . 38895 10 5 H) = . 0191116 H . 003 (part 1 of 2) 10.0 points The current in a 77 mH inductor changes with time as I = b t 2 a t . With a = 15 A / s and b = 5 A / s 2 , find the magnitude of the induced emf , E , at t = 1 . 3 s. Correct answer: 0 . 154 V. Explanation: Let : L = 77 mH = 0 . 077 H , b = 5 A / s 2 , a = 15 A / s , and t = 1 . 3 s . From Faradays Law, the induced emf E is proportional to the rate of change of the magnetic flux, which in turn is proportional to the rate of change of the current. This is expressed as E = L d I dt = L d dt ( b t 2 a t ) = L (2 b t a ) nguyen (jmn727) homework 26 Turner (59070) 2 At 1 .....
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