hw 28 - nguyen(jmn727 homework 28 Turner(59070 1 This...

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Unformatted text preview: nguyen (jmn727) homework 28 Turner (59070) 1 This print-out should have 10 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. 001 10.0 points A positively charged particle moving at 45 angles to both the x-axis and y-axis enters a magnetic field (pointing into of the page), as shown in the figure below. x y v z vector B vector B + q Figure: is in the x-direction, is in the y-direction, and k is in the z-direction. What is the initial direction of deflection? 1. hatwide F = 1 2 parenleftBig + k parenrightBig 2. hatwide F = 1 2 parenleftBig + k parenrightBig 3. hatwide F = 1 2 parenleftBig + k + parenrightBig 4. hatwide F = 1 2 ( + ) correct 5. hatwide F = 1 2 parenleftBig k + parenrightBig 6. hatwide F = 1 2 parenleftBig + k parenrightBig 7. hatwide F = 1 2 (+ ) 8. hatwide F = 1 2 (+ + ) 9. vector F = 0 ; no deflection 10. hatwide F = 1 2 parenleftBig + + k parenrightBig Explanation: Basic Concepts: Magnetic Force on a Charged Particle: vector F = qvectorv vector B Right-hand rule for cross-products. hatwide F vector F bardbl vector F bardbl ; i.e. , a unit vector in the F direc- tion. Solution: The force is vector F = qvectorv vector B . vector B = B parenleftBig + k parenrightBig , vectorv = 1 2 v (+ + ) , and q > , therefore , vector F = + | q | vectorv vector B = + | q | 1 2 v B bracketleftBig (+ + ) parenleftBig + k parenrightBigbracketrightBig = + | q | 1 2 v B ( + ) hatwide F = 1 2 ( + ) . This is the second of eight versions of the problem. 002 10.0 points A thin 2.50 m long copper rod in a uniform magnetic field has a mass of 58.1 g. When the rod carries a current of 0.287 A, it floats in the magnetic field. The acceleration of gravity is 9 . 81 m / s 2 . What is the field strength of the magnetic field? Correct answer: 0 . 794371 T. Explanation: Let : = 2 . 50 m , m = 58 . 1 g = 0 . 0581 kg , I = 0 . 287 A , and g = 9 . 81 m / s 2 . The magnetic and gravitational forces are equal: F m = F g nguyen (jmn727) homework 28 Turner (59070) 2 B I = m g B = m g I = (0 . 0581 kg) (9 . 81 m / s 2 ) (0 . 287 A) (2 . 5 m) = . 794371 T 003 10.0 points The figure represents two long, straight, par- allel wires extending in a direction perpendic- ular to the page. The current in the left wire runs into the page and the current in the right runs out of the page....
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hw 28 - nguyen(jmn727 homework 28 Turner(59070 1 This...

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