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Unformatted text preview: nguyen (jmn727) oldhomework 25 Turner (59070) 1 This printout should have 13 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. 001 (part 1 of 2) 10.0 points A rectangular loop coplanar to and located a distance 4 . 8 cm from a long wire carrying a current of 0 . 0239 A is shown in the figure. The wire is parallel to the longest side of the loop. 4 . 8cm 2 . 97 cm 28 . 4cm . 0239A Find the total magnetic flux through the loop. Correct answer: 6 . 53855 10 10 Wb. Explanation: Let : c = 4 . 8 cm , a = 2 . 97 cm , b = 28 . 4 cm , and I = 0 . 0239 A . c a b r dr I From Amp` eres law, the strength of the magnetic field created by the currentcarrying wire at a distance r from the wire is B = I 2 r , so the field varies over the loop and is directed perpendicular to the page. Since vector B is parallel to d vector A , the magnetic flux through an area element dA is integraldisplay B dA = integraldisplay I 2 r dA . Note: vector B is not uniform (it depends on r ), so it cannot be removed from the integral. In order to integrate, the area element shaded in the figure as dA = b dr . Since r is the only variable that now appears in the integral, the magnetic flux is B = I 2 b integraldisplay a + c c d r r = I b 2 ln r vextendsingle vextendsingle vextendsingle a + c c = I b 2 ln parenleftbigg a + c c parenrightbigg = (0 . 0239 A)(0 . 284 m) 2 ln parenleftbigg a + c c parenrightbigg = (0 . 0239 A)(0 . 284 m) 2 (0 . 481654) = 6 . 53855 10 10 Wb . 002 (part 2 of 2) 10.0 points What is the direction of the magnetic field through the rectangular loop? 1. Parallel to the plane of the paper and perpendicular to the current direction in the wire. 2. out of the plane of the paper 3. into the plane of the paper correct 4. Parallel to the plane of the paper and parallel to the current direction in the wire. Explanation: nguyen (jmn727) oldhomework 25 Turner (59070) 2 Using the righthand rule on the long straight wire, if the current flows upward (downward), the magnetic field would be into (out of) the plane of the paper. Consequently the magnetic field is directed into the plane of the paper. 003 (part 1 of 4) 10.0 points The circular loop of wire shown in the figure is placed in a spatially uniform magnetic field such that the plane of the circular loop is per pendicular to the direction for the magnetic field as shown in the figure. The magnetic field vector B ( t ) varies with time, with the time de pendence given by B ( t ) = a + b t , where a = 0 . 14 T and b = 0 . 049 T / s. The acceleration due to gravity is 9 . 8 m / s 2 ....
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This note was uploaded on 01/21/2010 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas at Austin.
 Spring '08
 Turner
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