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Unformatted text preview: nguyen (jmn727) – oldhomework 11 – Turner – (59070) 1 This printout should have 12 questions. Multiplechoice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 4) 10.0 points An airfilled capacitor consists of two parallel plates, each with an area of 5 . 8 cm 2 , sepa rated by a distance 2 . 6 mm . A 29 V potential difference is applied to these plates. The permittivity of a vacuum is 8 . 85419 × 10 − 12 C 2 / N · m 2 . 1 pF is equal to 10 − 12 F . The magnitude of the electric field between the plates is 1. E = 1 ( V d ) 2 . 2. E = parenleftbigg d V parenrightbigg 2 . 3. E = V d . 4. E = ( V d ) 2 . 5. None of these 6. E = 1 V d . 7. E = d V . 8. E = parenleftbigg V d parenrightbigg 2 . 9. E = V d . correct Explanation: Since E is constant between the plates, V = integraldisplay vector E · d vector l = E d E = V d . 002 (part 2 of 4) 10.0 points The magnitude of the surface charge density on each plate is 1. σ = ǫ V d . 2. σ = ǫ ( V d ) 2 . 3. None of these 4. σ = ǫ parenleftbigg V d parenrightbigg 2 . 5. σ = ǫ parenleftbigg d V parenrightbigg 2 . 6. σ = ǫ d V . 7. σ = ǫ ( V d ) 2 . 8. σ = ǫ V d 9. σ = ǫ V d . correct Explanation: Use Gauss’s Law. We find that a pillbox of cross section S which sticks through the sur face on one of the plates encloses charge σ S. The flux through the pillbox is only through the top, so the total flux is E S. Gauss’ Law gives σ = ǫ E = ǫ V d Alternatively, we could just recall this result for an infinite conducting plate (meaning we neglect edge effects) and apply it. 003 (part 3 of 4) 10.0 points Calculate the capacitance. nguyen (jmn727) – oldhomework 11 – Turner – (59070) 2 Correct answer: 1 . 97516 pF. Explanation: Let : A = 0 . 00058 m 2 , d = 0 . 0026 m , V = 29 V , and ǫ = 8 . 85419 × 10 − 12 C 2 / N · m 2 . The capacitance is given by C = ǫ A d = 8 . 85419 × 10 − 12 C 2 / N · m 2 × . 00058 m 2 . 0026 m = 1 . 97516 × 10 − 12 F = 1 . 97516 pF ....
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 Spring '08
 Turner
 Electrostatics, Work, Correct Answer, Electric charge, C1 C2 C12

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