# oldhw 15 - nguyen(jmn727 – oldhomework 15 – Turner...

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Unformatted text preview: nguyen (jmn727) – oldhomework 15 – Turner – (59070) 1 This print-out should have 11 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points The internal resistance r of a battery with emf E is connected to a load resistor with resistance R . I 10 V A B 13 Ω 112 Ω internal resistance Find the potential difference V BA = V A- V B . Correct answer: 8 . 96 V. Explanation: Let : E = 10 V , R = 112 Ω , and r = 13 Ω . The current through the circuit is i = E r + R , so the potential difference V A- V B is V A- V B = i R = E R r + R = (10 V) (112 Ω) 13 Ω + 112 Ω = 8 . 96 V . 002 (part 2 of 2) 10.0 points What is the power P dissipated by the load resistor R ? 1. P = r E 2 2. P = R E 2 3. P = E 2 r R 4. P = E 2 r + R 5. P = E 2 r 6. P = parenleftbigg E r + R parenrightbigg 2 r 7. P = E 2 R r 8. P = ( r + R ) E 2 9. P = parenleftbigg E r + R parenrightbigg 2 R correct 10. P = parenleftbigg E R parenrightbigg 2 r Explanation: The power dissipated by the load is P = i 2 R = parenleftbigg E r + R parenrightbigg 2 R . 003 (part 1 of 3) 10.0 points An electric heater is rated at 1250 W, a toaster is rated at 1040 W, and an electric grill is rated at 1550 W. The three appliances are connected in parallel across a 126 V emf source. Find the current in the heater. Correct answer: 9 . 92063 A. Explanation: Let : P H = 1250 W , P T = 1040 W , P G = 1550 W and Δ V = 126 V . P H = I H Δ V I H = P H Δ V = 1250 W 126 V = 9 . 92063 A . nguyen (jmn727) – oldhomework 15 – Turner – (59070) 2 004 (part 2 of 3) 10.0 points Find the current in the toaster....
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## This note was uploaded on 01/21/2010 for the course PHY 303L taught by Professor Turner during the Spring '08 term at University of Texas.

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oldhw 15 - nguyen(jmn727 – oldhomework 15 – Turner...

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