Quiz1Solution%20for%20Version%20A

Quiz1Solution%20for%20Version%20A - 1 1 Problem 1 mv 2 0 =...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
22 2 11 Problem 1. 0 0 2.23 / mv kx kx vm s m +=+ == Problem 2. 340 m/s / 0.00567 60000 Hz vf m λ = = Problem 3. cos(2 ) 6 1 2 2 / 5 0.0637 5 1/ 5 15.708sec xA f t Ac m f fH z Tf π = = =⇒ = = = Problem 4. 150 15000 / 0.01 Fk x x F N kN m xm =− = = ' 1 Problem 5. For Spring 2 1 For Pendulum 3 2 31 3 9 k f m g ff L kg f mL mg L k ππ = = Problem 6. Clock running fast means Period (T) is too small. To increase T (T 2 ), should increase. L L g = '' ' ' ' Problem 8. v (2 )(2L) v2 2 FF L m L F F L v mm m µ = = =
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
2 2 2 22 2 Problem 9. v(t) (2 )sin(2 ) ( ) ) cos(2 ) (0) ) 197.4 / 197.4 5 ) (0) 5 dx A ff t dt dx at A f f t dt aA f m s Am f xA m ππ π == =− Problem 10. The two wave just cancel each other.
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}

Page1 / 2

Quiz1Solution%20for%20Version%20A - 1 1 Problem 1 mv 2 0 =...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online