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problem37_08 - c u in terms of γ γ 2 1 1 γ 1 1 2 2-≈-=...

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37.8: a) The frame in which the source (the searchlight) is stationary is the spacecraft’s frame, so 12.0 ms is the proper time. b) To three figures, . c u = Solving Eq. (37.7) for
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Unformatted text preview: c u in terms of , γ . γ 2 1 1 ) γ 1 ( 1 2 2-≈-= c u Using . 998 . gives ms 190 ms . 12 γ 1 = = ∆ ∆ = c u t t...
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