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problem36_64

# problem36_64 - -=-× × =-= =-× × = =-=-= = = ′-= ×...

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36.64: a) As the rays first reach the slits there is already a phase difference between adjacent slits of . λ sin 2 θ π d This, added to the usual phase difference introduced after passing through the slits, yields the condition for an intensity maximum: λ ) sin (sin 2 λ sin 2 λ sin 2 m d m θ d θ d = + = + b) 600 . m 10 67 . 1 m 10 00 . 6 1 mm slits 6 1 5 - - × = × = d . 0 . 47 0 . 20 sin m 10 67 . 1 m 10 50 . 6 arcsin : 1 . 71 . 2 0 . 20 sin m 10 67 . 1 m 10 50 . 6 arcsin : 1 . 0 . 20 ) 0 . 20 sin arcsin( : 0 : 0 . 20 . 9 . 22 m 10 67 . 1 m 10 50 . 6 arcsin λ arcsin : 1 . 9 . 22 m 10 67 . 1 m 10 50 . 6 arcsin λ arcsin : 1 . 0 ) 0 arcsin( : 0 : 0 6 7 6 7 6 7 6 7
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Unformatted text preview: -= -× × =-= = -× × = =-=-= = = ′-= × ×-= -=-= = × × = = = = = = = ′--------m m m d m d m m...
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