problem36_47

problem36_47 - s D s y 22 . 1 = Hubble: D = 2.4 m and 400 =...

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36.47: Let y be the separation between the two points being resolved and let s be their distance from the telescope. Then the limit of resolution corresponds to 1.22 s y D = λ a) Let the two points being resolved be the opposite edges of the crater, so y is the diameter of the crater. For the moon, m. 10 8 . 3 8 × =
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Unformatted text preview: s D s y 22 . 1 = Hubble: D = 2.4 m and 400 = nm gives the maximum resolution, so y = 77 m Arecibo: D = 305 m and 6 10 1 . 1 ; m 75 . = = y m b) 22 . 1 yD s = Let 30 . y (the size of a license plate) km 1500 m)] 10 [(1.22)(40 m) (2.4 m) 30 . ( 9 = =-s...
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problem36_47 - s D s y 22 . 1 = Hubble: D = 2.4 m and 400 =...

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