problem36_22

problem36_22 - φ sin β 2 and must calculate the phases φ...

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Unformatted text preview: φ sin( β 2) , and must calculate the phases φ and β . 36.22: We will use I = I 0 cos 2 β 2 πa 2πd sin θ , and φ = sin θ , we have: Using β 2 = λ λ −4   a)  θ = 1.25 × 10 rad : β 2 = 0.177(10.1°), and φ = 1.01(57.9°) ⇒ I = 0.757 I 0 . 2 −4   b)  θ = 2.50 × 10 rad : β 2 = 0.355(20.3°), and φ = 2.03(116.3°) ⇒ I = 0.268 I 0 . −4   c)  θ = 3.00 × 10 rad : β 2 = 0.426(24.1°), and φ = 2.43(139.2°) ⇒ I = (0.114) I 0 . 2 ...
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This note was uploaded on 01/24/2010 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.

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