problem36_16

problem36_16 - From the diagram, it is clear that the total...

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36.16: The total intensity is given by drawing an arc of a circle that has length 0 E and finding the length of the cord which connects the starting and ending points of the curve. So graphically we can find the electric field at a point by examining the geometry as shown below for three cases. a) . 2 λ λ 2 sin λ 2 π θ β = = = a a a From the diagram, . 2 2 0 0 E E E E p p = = So the intensity is just: . 4 2 2 0 0 2 I I I = = This agrees with Eq. (36.5). b) . 2 λ λ 2 sin λ 2 = = = a a a
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Unformatted text preview: From the diagram, it is clear that the total amplitude is zero, as is the intensity. This also agrees with Eq. (36.5). c) . 3 2 3 2 sin 2 = = = a a a From the diagram, . 3 2 2 3 E E E E p p = = So the intensity is just: . 9 4 3 2 2 2 I I I = = This agrees with Eq. (36.5)....
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