problem36_08

problem36_08 - 36.8: a)  E = Emax sin( kx − ω t ) 2π...

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Unformatted text preview: 36.8: a)  E = Emax sin( kx − ω t ) 2π 2π 2π k= →λ= = = 5.24 × 10 −7 m 7 −1 λ k 1.20 × 10 m c 3.0 × 108 m s fλ=c→ f = = = 5.73 × 1014 Hz λ 5.24 × 10 −7 m b)  a sin θ = λ a= c)  a sin θ = mλ (m = 1,2,3,. . . ) 5.24 ×10 m λ sin θ 2 = ±2 D = ± 2 1.09 ×10−6 m −7 λ 5.24 × 10 −7 m = = 1.09 × 10 −6 m sin θ sin 28.6° θ 2 = ±74 ...
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This note was uploaded on 01/24/2010 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.

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