problem36_06

problem36_06 - 36.6: a)According to Eq. 36.2 m m sin ( ) =...

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36.6: a) According to Eq. 36.2 a a m a m θ λ λ 1 ) 0 . 90 ( sin λ ) ( sin = = = ° = = Thus, mm. 10 5.80 nm 580 λ . 4 - × = = = a b) According to Eq. 36.7 [ ] [ ] . 128 . 0 ) (sin ) (sin sin ) (sin ) (sin sin 2 4 4 2 0 =
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This note was uploaded on 01/24/2010 for the course PHYS 208 taught by Professor Ross during the Spring '08 term at Texas A&M.

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