practiceexamanswers - Subject:PRACTICEEXAMANSWERS(complete)

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Subject:  PRACTICE EXAM ANSWERS (complete) Author:  Blake Joseph Abawi Date:  Friday, December 1, 2006 11:57pm these are just my thoughts, so please look at them very critically. enjoy. Part A: A. 36 B. 39 C. 23 D. 12 E. 19 F. 16 G. 11 H. 13 I. 32 J. 35 K. 37 L. 41 M. 8 Part B: 1. b 2. a 3. a 4. a 5. e 6. g 7. f 8. N/A? 9. N/A 10. b 11. c 12. a 13. N/A 14. b 15. b 16. b 17. c (this is a complete guess) 18. c 19. c 20. d Part C: 1. a) Hexokinase b) This reaction is not considered to be the committed step in glycolysis. This is because, while the reactions is not reversible, the product (glucose- 6-phosphate_ can still be used to form glycogen. Therefore, because this step does not commit its product to glycolysis only, it is not the committed step (excuse the redundancy). c) -30.5 + 20.9 = -9.6 kj/mole d) ans: 0.194 -value is different from part c because of the difference in temp at physiological conditions. Furthermore, in this case, the reaction is not at equilibrium e) This liver’s main task is to maintain appropriate blood glucose levels. The production of glucose-6-phosphate has little relevance to this task (at best it is an inefficient precursor to glycogen), so the isozome of enzyme A found in the liver has appropriately little affinity for glucose. However, this Enzyme A is useful in glycolysis, something which the liver performs only at times of very hi [glucose]. It therefore makes sense that Enzyme A would have a low affinity for glucose, so as to only be “active” during times of
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practiceexamanswers - Subject:PRACTICEEXAMANSWERS(complete)

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