Unformatted text preview: the angle between two planes ;→ n 1 •→ n 2 = 11 = 0 . Since the dot product is zero, they are orthogonal, i.e., the angle between two planes is π/ 2. 3. Find the parametrization of the intersection curve of the plane y = 1 2 and the sphere x 2 + y 2 + z 2 = 1. Ans. Since y is given by 1 / 2, the second surface becomes x 2 + z 2 = 3 / 4 which is an equation of a circle centered at the origin with radius √ 3 / 2. So we parametrize the circle by x = √ 3 2 cos t , z = √ 3 2 sin t and so, the parametrization of the intersection curve is r ( t ) = * √ 3 2 cos t, 1 2 , √ 3 2 sin t + ....
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 Fall '08
 Lunasin
 Math, Dot Product, normal vectors, intersection curve

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