Detrmining the ultimate load values

Detrmining the ultimate load values - Ultimate load values:...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Detrmining the ultimate load values : Weight of the slab (for beams): Let us consider 7 hollow block/m2,and the thickness of the slab of 30 cm, we can write: V(hordis/m 2 )=7*(0.4*0.2*0.24)=0.1344 m3/m2 V(concrete/m 2 )=0.3-0.1344=0.1656 m3/m2 Therefore the weight of the slab is :W(slab)=0.1344*1000+0.1656*2500=548.4 kg/m 2 . Weight of the slab (for ribs): Each rib must support all the surcharges and transmit them to the beams (5hollow blocks/m2),we can write : V(hordis/m 2 )=(1/0.57)*(5*0.4*0.2*0.24)=0.168 m3/m2 V(concrete/m 2 )=0.3-0.168=0.1315 m3/m2 Therefore the weight of the slab is :W(slab)=0.168*1000+0.1315*2500=497 kg/m2
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
Background image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Ultimate load values: The different kinds of loads acting on a slab are: For interior zone: D.L : partition =250 kg/m2 Tiling = 200 kg/m2 L.L : surcharges =250 kg/m2. For beams : q(u1)=1.2(548.4+250+200)+1.6(250)=1.59 T/m 2 For ribs: q(u1)=1.2(497+250+200)+1.6(250)=1.53 T/m 2 For Exterior zone: D.L : partition =250 kg/m2 Tiling = 200 kg/m2 L.L : surcharges =250 kg/m2 for beams: q(u2)=1.2(548.4+150+200)+1.6(500)=1.87 T/m 2 for ribs: q(u2)= 1.2(497+150+200)+1.6(500)=1.81 T/m 2...
View Full Document

This note was uploaded on 01/27/2010 for the course DS csc 270 taught by Professor Dr.m.g during the Spring '10 term at Notre Dame University-Louaize.

Page1 / 2

Detrmining the ultimate load values - Ultimate load values:...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online