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# Twowayslab - Design of an interior flat plate Fy=420MPa...

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Design of an interior flat plate Fy=420MPa F’c=28MPa Weights acting on a slab for interior zone are: D.L: partition=250 kg/m 2 Tiling=200 kg/m 2 L.L: Surcharges=250 kg/m 2 1. Minimum Thickness: L1=3.65m L2=2.3m Column dimensions are: 20*25 cm Interior Panel : α=0 Ln=3.65-0.25=3.4m (clear distance between columns) Min h =ln/33 (from table 9.5© -ACI 318M) -For fy=420 MPa and interior panel: Min h =3.44/33=0.10303 m=103 mm<120 mm - l 1 /l 2 =3.65/2.3=1.58<2 And from ACI code ,section 9.5.3.2: Min thickness for slab without drop panels is : 120 mm ok Assume h=160 mm 2. Check For Shear: -Determine depth required for shear (using d for shear equal to the estimated average of the d values in the two directions): D=160-20-10=130 mm Wu=1.2(250+200)*9.81+1.6(250)*9.81=9.2214 KN/m 2

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---Checking for one-way or beam shear : V u1 = (1570/1000)*9.2214=14.4775 KN= 14477.5 N (for 200 mm width) ACI 318M(11.3.1.1) =34394.76 N >14477.5 N ok ---Checking for two-way or punching shear around the column:
(b 0 )=2(200+130)+2(250+130)=1420 mm V u2 =[(3.65*2.3)-(0.25+0.13)*(0.2+0.13)]*9.2214=76.257 KN= 76257 N φVc for non prestressed slabs: >76257 N ok therefore we use h=160 mm Note that the design is conservative. 3. Calculate Static Moments : 4. Proportioning The Static Moments To The Column And Middle Strips And Select

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Twowayslab - Design of an interior flat plate Fy=420MPa...

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