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fall 08 exam 2 - Chem 3321 Physical Chemistry I Fall 2008...

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Unformatted text preview: Chem 3321 Physical Chemistry I Fall, 2008 November 10, 2008 ' Exam 2 Name YOU MAY WO ‘1’ ANY FOUR PROBLEMS FOR FULL CREDIT. NO EXTRA CREDIT WILL BE OWEN FOR WORKING MORE THAN FOUR PROBLEMS. PLEASE MARK THOSE PROBLEMS YOU WANT GRADED OR ELSE YOUR FIRST 4 PROBLEMS m BE GRADED. Useful constants: R = 8.314 Jan-K = (11182 L-amfim—K Ideal Menaiemie gas: C“... = 3:2 R Cm = 5:2 R T [cm H I _ T =1: 11-] J“ ' Ic,.,.,+Ri dU = TdS -_ PMF dH = TciS + V'dP 6A = -SdT — PMr :16: = -SdT + VdP [3%]:[2—3 [$]3=[%%l [filfil {EARL Useful expressions: R |n[?‘r] = CM ]R[ 1. Using the expressions for the combined First and Second Law and Maxwell’s relationships show that (a) Odh‘m‘s 4N”? . @331: 1%)“: HI = Ssgagu GIL-LE). (h) Eyaluate the expression for an ideal gas =ntz—' 31 “Mi 5’ s? Kfi-fi' ”E9— %§T='TQ‘%*V = ”Wig 2. One mole of an ideal gas with Cam: SEE R undergoes the transformations described in the following list fi'orn an initial state described by T = 2513 K and P = LDC! atrn. Calculate :31, w, 3U, dH, asses and 11*.ng for each processJITsllnr = 251‘.) K) a. The gas undergoes a tea ' 1e adiabatic expansion until the final pressure is half its initial value. it an? s (immig- «535i? Merges—mt his ”$5M an *' .L as \33 3p» m- cm Carin ~ as Kane-vow» but: C$MBT= PIQLME‘i'Sfi-in— Bees—so: Manta} b The gas undergoes an adiabatic expansion against a constant external pressure of l]. SUE} aim until the final pressure is half its initial value TV "E, kc",_,—D“i?‘ i“ 3w L“ '1“— Law“ or) Eli-1.1+?) '5’?“ m= has ‘- EELi-i‘ir'lm‘i' '— '73.“: 1:11;; boa—asst hemifi - c. The gas undergoes an isofl1ennai expansio r IIISt a constant external pressure of zero atrn until the final pressure is equal to haif of Its initial value. _ ”“— —. gs. (I) Sash— PE?" 15‘3““ as: act. was hm© 3. The densities: of a given solid and liquid ef molecular weight l22.5 at its normal melting temperature of 42115 K are HHS and 1012 kgfin3, reapeetively. If the preeewe is increased to 120 bar, the melting temperature increases te 429.35 K. Calculate all-fig and 3.5"“. a -3 a. meat *‘i 3 “4% A,” I17; $1.10 fiklflfllI—J‘L’Iflmfi ”1.5%: if: «A War: here are. We"? but,“ "Raffle; -h I, - . H‘Umr wa 1mm we) twigs 4. The vapor pressure of benzene {MW TB gmol] is 53.3 kPa at 61116 ‘}IE but it fell to 51.5 kPa when 19.1} g of an non-volitile organic compound was dissolved in SDI} g of benzene. Calculate the molar mass of the compound. 5. The degree of dissociation, at, of {302(g} into C0(g} and (Mg) aeeording to the reaction {302(3) 9 0mg) + V2 Die) {The degree of dissociation is defined such that if isJ moles of C02 was inundueed into a flask the number of moles OfCDz remaining at equilibrium would be [IOU-{15D At high temperatures oz.a was found to vary with temperature as follows: To: 1395 1443 1493 suit)“ 1.44 2.50 4.11 - a. Write an expression of the equilibrium constant RF in terms of as. a £0.39 4 Co + V101? 1 5 is New moor) was? Vii was: ELL-24?? ls“ ‘1 u “‘L .1}- “LP A- are; r" .1- a"; r? if 5H»; b. Calculate so“ an“ and as“ at 1443 K, assuming aH" and as" are temperature independent. 3’ ”'3 .e I: K Uni-t3) - Queue '5 1' EL. = inch—to ail} . 4i +§ N2" '= 41‘? 3M?- 43 AWLI-wswLmtsn— m 16—5 a g; ‘ 40 as men \cg- Lga:s‘*j”ts_ : Uri-“U " filk“ 51,4041. :1). -A‘r}. Lifts Etta: Q‘ibufi ) AH-l his“ “1. mgr be°_ QR Mgvtagfistea st Age tees ...
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