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Unformatted text preview: Chem 3321
Physical Chemistry I
Fall, 2008
November 10, 2008 ' Exam 2 Name YOU MAY WO ‘1’ ANY FOUR PROBLEMS FOR FULL CREDIT. NO EXTRA CREDIT WILL BE
OWEN FOR WORKING MORE THAN FOUR PROBLEMS. PLEASE MARK THOSE PROBLEMS YOU WANT GRADED OR ELSE YOUR FIRST 4
PROBLEMS m BE GRADED. Useful constants: R = 8.314 JanK = (11182 Lamﬁm—K
Ideal Menaiemie gas: C“... = 3:2 R Cm = 5:2 R T [cm H I
_ T =1:
11] J“ ' Ic,.,.,+Ri dU = TdS _ PMF dH = TciS + V'dP 6A = SdT — PMr :16: = SdT + VdP [3%]:[2—3 [$]3=[%%l [ﬁlﬁl {EARL Useful expressions: R n[?‘r] = CM ]R[ 1. Using the expressions for the combined First and Second Law and Maxwell’s relationships show
that (a) Odh‘m‘s 4N”? . @331: 1%)“: HI = Ssgagu GILLE). (h) Eyaluate the expression for an ideal gas =ntz—' 31 “Mi
5’ s? Kﬁﬁ' ”E9— %§T='TQ‘%*V = ”Wig 2. One mole of an ideal gas with Cam: SEE R undergoes the transformations described in the
following list ﬁ'orn an initial state described by T = 2513 K and P = LDC! atrn. Calculate :31, w, 3U,
dH, asses and 11*.ng for each processJITsllnr = 251‘.) K) a. The gas undergoes a tea ' 1e adiabatic expansion until the ﬁnal pressure is half
its initial value. it an? s (immig
«535i? Merges—mt his ”$5M an
*' .L as \33 3p» m cm Carin ~ as Kanevow» but: C$MBT= PIQLME‘i'Sﬁin—
Bees—so: Manta} b The gas undergoes an adiabatic expansion against a constant external pressure of
l]. SUE} aim until the ﬁnal pressure is half its initial value TV "E, kc",_,—D“i?‘ i“ 3w L“ '1“—
Law“ or) Eli1.1+?) '5’?“ m= has ‘ EELii‘ir'lm‘i' '—
'73.“: 1:11;; boa—asst hemiﬁ  c. The gas undergoes an isoﬂ1ennai expansio r IIISt a constant external pressure
of zero atrn until the final pressure is equal to haif of Its initial value. _
”“— —. gs. (I) Sash— PE?" 15‘3““ as: act. was hm© 3. The densities: of a given solid and liquid ef molecular weight l22.5 at its normal melting
temperature of 42115 K are HHS and 1012 kgﬁn3, reapeetively. If the preeewe is increased to 120 bar, the melting temperature increases te 429.35 K. Calculate allﬁg and 3.5"“. a 3 a. meat *‘i 3
“4% A,” I17; $1.10 ﬁklﬂﬂlI—J‘L’Iﬂmﬁ ”1.5%: if: «A War: here are.
We"? but,“ "Rafﬂe; h I,
 . H‘Umr wa 1mm we) twigs 4. The vapor pressure of benzene {MW TB gmol] is 53.3 kPa at 61116 ‘}IE but it fell to 51.5 kPa when 19.1}
g of an nonvolitile organic compound was dissolved in SDI} g of benzene. Calculate the molar mass of the compound. 5. The degree of dissociation, at, of {302(g} into C0(g} and (Mg) aeeording to the reaction {302(3) 9 0mg) + V2 Die) {The degree of dissociation is deﬁned such that if isJ moles of C02 was inundueed into a ﬂask the number
of moles OfCDz remaining at equilibrium would be [IOU{15D At high temperatures oz.a was found to vary with temperature as follows: To: 1395 1443 1493
suit)“ 1.44 2.50 4.11  a. Write an expression of the equilibrium constant RF in terms of as. a £0.39 4 Co + V101? 1
5 is New moor) was? Vii was: ELL24?? ls“
‘1 u “‘L .1}
“LP
A
are;
r"
.1
a";
r?
if
5H»; b. Calculate so“ an“ and as“ at 1443 K, assuming aH" and as" are temperature independent.
3’ ”'3 .e I:
K Unit3)  Queue '5 1' EL. = inch—to ail} . 4i
+§ N2" '= 41‘? 3M? 43 AWLIwswLmtsn— m 16—5 a g; ‘ 40
as men \cg Lga:s‘*j”ts_ : Uri“U
" ﬁlk“
51,4041. :1). A‘r}. Lifts Etta: Q‘ibuﬁ ) AHl his“ “1.
mgr be°_ QR Mgvtagﬁstea st Age tees ...
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