fall 06 exam 3 - Physical CthlStl'y I CHEM 3321 Exam #3...

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Unformatted text preview: Physical CthlStl'y I CHEM 3321 Exam #3 Fall, secs Name l. The reaction mo + H2—"——-— Ngo + H20 has been proposed to proceed by the mechanism It ‘ N202 k_. k H2 ‘l' N202 2- N20 + (Slaw) 2ND Derive an expression for the rate constant k in the rate law {LPNng 2 I = r F assuming (a) steady-state approximation for N20; {h} a fast equilibrium in step i. (c) Under what conditions are the two expressions equal? (d) how would you design an experiment to tell them apart? . so . " ‘- J [LE-m “- 1‘3 Pm ‘ k—fi‘lmioer Leaflm‘t-‘h. C 13$ _' h.I-lr-r’ts:. _ __ it, A! Link-f “D ’ dcjgmu I. in I x, at? 5 ltLhEeeF‘Lt?" u = . - d. x a. 11 “43’; L Edi-{1 IQJ Ill-:7 a -_ if) \ h- ELth - _ \ {xi-*4“ if“? is? -i _ J 1—" *‘1 '1, on \< K trig— or “r: m _ I ‘rk q“ ,. 'L _ __ '.I ° ,. » . c K t 9m e. ete- .. L: — 4H 1. "--.« -. .r- I \\ll :L \Q.11' '-'-._ ‘51-‘41 ‘- H- '.__\-I . II II - — ___ 'II" L-n “'1. x‘h: u I (I 3 WII'W 19% ‘C ‘1 "L‘s—"vii. {Ex} iitiiil'vnmunus'i. Q‘E ~ 5"- - ' a” g, ._____ ___ _ . -. __‘l '. _ 'I it Kim. m; . x. "3* 1p. “it”; trme cu “x.- t n. :31“ Lét VNQX lo; hm. “xi-1333‘ __ _ ._ 2. The half—life for the (firm-order) radiumtive decay 0f “C is 5TH} years. An archaeological samplc mntained wood that had 0:11ngr 7'2 percent ofthc “C fflllfld in living trees. What is its age? 9% a vs. “my *- u— - = E. in \r HQ? L h kw: tfl'ifl Yam: flaw-a Kafl ) hip-Hg): n Lighxtgjingii: Ham-31?. “ruin Lg, H Li . The rate constant, k4, for a difiusion controlied reaction is 4mmDNo, where No is Avagadro‘snumber, firm” = ‘fimd D = DIM + DN,the sum ofthe diffusion coeflicients. Using flIEHStEifl equation D = kanfimir, derive an expression for 1c; which depends on R. T and 11. (b) Calculate the magnitude of kg at 293 K for a species in water. The 1viscosityr of water is Lilli} x 113' kg m" s". 4:. 1| i. ‘— b‘g‘l— _ Jr F"- - g‘ D DH TL“ GD“ Ti FM (9“ «oil fu {4111 rp em out"? sum ’ewc “m 4. The decomposition of urea in [1.1 M HCl occurs aocording to the reaction NI—IECCINH; + 2H1CI —) 2m: + films"2 The first order rate constant for this reaction was measured as a function of temperature, with the following results: LL .F —-— £351; ___ r: J _- l1 J'ng '53-“) *L ‘ _ E2: — Flt—"d _— K‘BEO If?“ 15%“ .'L llg‘fiul .. - #1 _ .. w . x H - 3 “lbfinflé_ f: L” I ll“ _._ _.._ -..‘+fv‘-+l~ l m . __thfihrf‘ P l; E Bff'uh fl _ mk‘r’m i I go; Loilkgi‘i} (.3 1191?; {I‘lfiflfigi 10—1.: E l‘" {n.(pflwo "l TEN: moire; _rwfitt. “daifihfifimtjht Q barre. garage, ‘- {'1 9;” —_. '51. D c: ‘3 {MW-lg?) {or n T of: m.tfifoe=~>erom 'I" '5 r:- t; & R. ""l t 'x \___ . 5. An important step in the blood coagulation process is the enzymatic conversion of the protein proflironthin to the lower—molecular weight clotting agent, thromhin, via cleavage ofa portion of the prothrornhin polypeptide. Prothromhin -) thromhin + cleaved peptide The 1values of 52.1w and Elm,w for prothromhin have been found to be 4.35 3: HT” sec and 6.24 x lfl"F cm2 see'lr respectively. The diffusion coefficient for thromhin is 3.7-5 x 10'? cm1 sec". Assume that both thrombin and prothrornhin are unhydrated spheres with $2 = ll?!) cm3 g'[ and calculate the molecular weights of prothrotnhin, thrornhin, and the cleaved peptide. “f 4 t-x fin: 5" -“-*'1 ‘1‘- ? il- ’-'v-4 '5 ‘3 3*“4-1""‘-' I H ; 33H 5 “Kill-3 17 "£5111 - TI ‘1 r 1?, I I 1% Bath's-I :_ “It 31 '- E31 flmqlw‘f-‘I'C I:l._h:d~q*fid;i*—Hn _ I 5 1 (Liars-ts as aw? a") it ~ to?- Dhéease-zv- .- '—-'.IK{O‘E.JI_ {JCI r: 2- ref -_|' GI *3 ti 3 :31 a +.-_ *- ‘l . i ' ‘“ '1 N k lumen”- ;- '- ID . no: :ch emu“) €1.31? El. ‘r‘aksrek‘l‘fm " we ~ 1 “a * Heed t ...
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This note was uploaded on 01/27/2010 for the course CHEM 3321 taught by Professor Goux during the Fall '09 term at University of Texas at Dallas, Richardson.

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fall 06 exam 3 - Physical CthlStl'y I CHEM 3321 Exam #3...

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