explore1 - Linear Algebra Explore Assignment 1 I. Exercise...

Info iconThis preview shows pages 1–4. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Linear Algebra Explore Assignment 1 I. Exercise on Linear Systems (a). A = [1 1 1 1 | 0 ] [ 1 2 2 2 | - 4] [0 -3 2 1 | 10] [-2 0 0 1 | 4 ] (b). B = [1 0 0 0 | 4 ] [ 0 1 0 0 | - 6 ] [ 0 0 1 0 | - 10] [0 0 0 1 | 12 ] (c). Yes, x4 =12, x3 = -10, x2 = -6, and x1 = 4. (d). A = [1 1 1 1 | 0 ] [ 2 2 2 2 | - 4] [0 -3 2 1 | 10] [-2 0 0 1 | 4 ] (e). ). C = [1 0 0 -.5 | 0] [0 1 0 .4 | 0] [0 0 1 1.1 | 0] [0 0 0 0 | 2] (f). No, because the last row is all zeros and has inconsistency equal 2. (g). B is in the reduced echelon form and C isnt. C has rows 1 through 3 equaling to zero while the last row is 2. This means that B has a unique solution while C does not have a solution. I I. Finding Polynomials Cardiac Hill (a). A = [0 0 1 | 5] [1 1 1 | 3] [9 3 1 | 2] B = [1 0 0 | .5 ] [0 1 0 | -2.5] [0 0 1 | 5 ] a = .5 b = -2.5 c = 5 (b). (c). (0,5), (1,3), (3,2), and (2,10). (0^3)a + (0^2)b + (0)c + 1d = 5 (1^3)a + (1^2)b + (1)c + 1d = 3 (3^3)a + (3^2)b + (3)c + 1d = 2 (2^3)a + (2^2)b + (2)c + 1d = 10 A = [0 0 0 1 | 5 ] [1 1 1 1 | 3 ] [27...
View Full Document

Page1 / 9

explore1 - Linear Algebra Explore Assignment 1 I. Exercise...

This preview shows document pages 1 - 4. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online