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# explore1 - Linear Algebra Explore Assignment 1 I Exercise...

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Unformatted text preview: Linear Algebra Explore Assignment 1 I. Exercise on Linear Systems (a). A = [1 1 1 1 | 0 ] [ 1 2 2 2 | - 4] [0 -3 2 1 | 10] [-2 0 0 1 | 4 ] (b). B = [1 0 0 0 | 4 ] [ 0 1 0 0 | - 6 ] [ 0 0 1 0 | - 10] [0 0 0 1 | 12 ] (c). Yes, x4 =12, x3 = -10, x2 = -6, and x1 = 4. (d). A = [1 1 1 1 | 0 ] [ 2 2 2 2 | - 4] [0 -3 2 1 | 10] [-2 0 0 1 | 4 ] (e). ). C = [1 0 0 -.5 | 0] [0 1 0 .4 | 0] [0 0 1 1.1 | 0] [0 0 0 0 | 2] (f). No, because the last row is all zeros and has inconsistency equal 2. (g). B is in the reduced echelon form and C isn’t. C has rows 1 through 3 equaling to zero while the last row is 2. This means that B has a unique solution while C does not have a solution. I I. Finding Polynomials – Cardiac Hill (a). A = [0 0 1 | 5] [1 1 1 | 3] [9 3 1 | 2] B = [1 0 0 | .5 ] [0 1 0 | -2.5] [0 0 1 | 5 ] a = .5 b = -2.5 c = 5 (b). (c). (0,5), (1,3), (3,2), and (2,10). (0^3)a + (0^2)b + (0)c + 1d = 5 (1^3)a + (1^2)b + (1)c + 1d = 3 (3^3)a + (3^2)b + (3)c + 1d = 2 (2^3)a + (2^2)b + (2)c + 1d = 10 A = [0 0 0 1 | 5 ] [1 1 1 1 | 3 ] [27...
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explore1 - Linear Algebra Explore Assignment 1 I Exercise...

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