Is Curl of A perpendicular to A

Is Curl of A perpendicular to A - 1 Is it correct to say...

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Unformatted text preview: 1. Is it correct to say that ~ ∇× ~ A is a vector field that is perpendicular to ~ A because it is a cross product of ~ ∇ and ~ A ? Answer: Answer is NO! For example, one can show ~ ∇× ~ A is not necessarily perpendicular to the vector ~ A , as one would expect from a cross product. We will show this by an explicit construction. Choose ~ A =- ay ˆ i + bx ˆ j + c ˆ k ; where a , b and c are non-zero positive constants. ~ ∇ × ~ A = ( a + b ) ˆ k . The scalar product of ~ ∇ × ~ A and ~ A is ( a + b ) c 6 = 0. The field lines of the vector field ~ A look like a cork screw and its curl points towards the advancing direction of the screw given by the right hand rule. On the other hand the field also has a non-zero component in the direction in which the screw advances. It is not surprising that they are not perpendicular. What then makes ~ ∇ × ~ A a vector field? ~ ∇ × ~ A is a vector field because its components transform like one. For a similar reason ~ ∇ · ~ A is not a simple dot product. For example, ~ ∇ · ~ A 6 = ~ A · ~ ∇ . It is a scalar field because it does not change under a general rotation in the three dimensional space. 1 2. A charge Q is distributed uniformly over a sphere of radius R. Express the resulting volume charge density involving Dirac- δ function. Answer: The charge density is independent of the angles θ and φ and a function of r alone, i.e. ρ ( ~ r ) ≡ ρ ( r ). Charge density is zero for all values of r except at r = R . When charge density is integrated over all space (integration over the entire domains of θ and φ gives 4 π ,) one must get the total charge Q . Thus the integration of ρ ( r ) over r is finite even though the function is nonzero only ar r = R . It is possible only if charge density has an integrable....
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This note was uploaded on 01/28/2010 for the course PHYS 351 taught by Professor Gangopashyaya during the Spring '09 term at Loyola Chicago.

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Is Curl of A perpendicular to A - 1 Is it correct to say...

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