Solution_Phys351_Test1_2006

Solution_Phys351_Test1_2006 - Dr Gangopadhyaya Test I...

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Unformatted text preview: Dr. Gangopadhyaya Test I Physics 351 February 20, 2006 To receive full credit you must show your work in a neat, organized and a legible form. First five problems are worth 14 points each and the last problem is worth 30 points. Einstein summation convention assumed NO NAME ON THIS PAGE Eijk = ei . (ej x ek) Eijk Eimn = (jjm(jkn- (jjn(jkm (.4 X B)i = EijkAjBk I ~ p(r') dT' 41TEO IT - f'1 I 1 p(r') (r- r') , dT 41TEO If'- f'13 1. 14 Pts. Using E-symbol, show that .4. (B x C) = (.4 x B) . c. A .@.JC c) = ~Ai. (i)(c), = Ai € ijK "BjCIe. :. (Et:ij At Bj) (Ie. (X ~ 8)" C" 1- ... :: \" 'J( i ) . c. (.4. B) = AiBi Electrostatic potential: V(f')- Electric field: E(r)--- 2. 14 Pts. Three adjacent sides of a rectangular parallelopiped are 2, 3, and 4 units long respectively. Determine the angle between two body diagonals d~ and d-; that ~ connect points (0,0,0) to (2,3,4) and (2,0..4) to (0,3,0) respectively....
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This note was uploaded on 01/28/2010 for the course PHYS 351 taught by Professor Gangopashyaya during the Spring '09 term at Loyola Chicago.

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Solution_Phys351_Test1_2006 - Dr Gangopadhyaya Test I...

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