kraft-mcmillan - Proof of Kraft-McMillan theorem * Nguyen...

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Unformatted text preview: Proof of Kraft-McMillan theorem * Nguyen Hung Vu † 16 2 24 1 Kraft-McMillan theorem Let C be a code with n codewords with lenghth l 1 ,l 2 ,...,l N . If C is uniquely decodable, then K ( C ) = N X i =1 2- l i ≤ 1 (1) 2 Proof The proof works by looking at the nth power of K ( C ) . If K ( C ) is greater than one, then K ( C ) n should grw expoentially with n. If it does not grow expoentially with n, then this is proof that P N i =1 2- l i ≤ 1 . Let n be and arbitrary integer. Then h P N i =1 2- l i i n = = “ P N i 1 =1 2- l i 1 ” ··· “ P N i 2 =1 2- l i 2 ”“ P N i N =1 2- l in ” and then " N X i =1 2- l i # n = N X i 1 =1 N X i 2 =1 ··· N X i n =1 2- ( l i 1 + i 2 + ··· + in ) (2) The exponent l i 1 + l i 2 + ··· + l i n is simply the length of n codewords from the code C . The smallest value this exponent can take is greater than or equal to n, which would be the case if codwords were 1 bit long. If l = max { l 1 ,l 2 , ··· ,l N } then the largest value that the exponent can take is less than or equal to nl . Therefore, we can write this summation as K ( C ) n = nl X n A k 2- k where A k is the number of combinations of n codewords that have a combined length of k. Let’s take a look at the size of this coeficient. The number of possibledistinct binary sequences of length k is 2 k . If this code is uniquely decodable, then each se- quence can represent one and only one sequence of codewords. Therefore, the number of possible combinations of codewords whose combined length is k cannot be greater than 2 k . In other words, A k ≤ 2 k . * Introduction to Data Compression, Khalid Sayood † email: [email protected] This means that K ( C ) n = nl X k = n A k 2- k ≤ nl X k = n 2 k 2- k = nl- n + 1 (3) But K ( C ) is greater than one, it will grow exponentially with n, while n ( l- 1)+1 can only grow linearly, So if K ( C ) is greater than one, we can always find an n large enough that the inequal- ity (3) is violated. Therefore, for an uniquely decodable code C , K ( C ) is less than or equal ot one. This part of of Kraft-McMillan inequality provides a necces- sary condition for uniquely decodable codes. That is, if a code is uniquely decodable, the codeword lengths have to satisfy the inequality. 3 Construction of prefix code Given a set of integers l 1 ,l 2 , ··· ,l N that satisfy the inequality N X i =1 2- l i ≤ 1 (4) we can always find a prefix code with codeword lengths l 1 ,l 2 , ··· ,l N . 4 Proof of prefix code constructing theorem We will prove this assertion by developing a procedure for con- structing a prefix code with codeword lengths l 1 ,l 2 , ··· ,l N that satisfy the given inequality. Without loss of generality, we can assume that l 1 ≤ l 2 ≤ ··· ≤ l N . (5) Define a sequence of numbers w 1 ,w 2 , ··· ,w N as follows: w 1 = w j = P j- 1 i =1 2 l j- l i j > 1 ....
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This note was uploaded on 01/26/2010 for the course COMPUTER S 15-853 taught by Professor Guyblelloch during the Fall '09 term at Carnegie Mellon.

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kraft-mcmillan - Proof of Kraft-McMillan theorem * Nguyen...

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