# hw5 - EECS 203 Homework 5 Solutions Section 3.2 1(E 2abd a...

This preview shows pages 1–2. Sign up to view the full content.

EECS 203: Homework 5 Solutions Section 3.2 1. (E) 2abd a) Yes since 17x + 11 ≤ 17x + x = 18x ≤ 18x 2 for all x ≥ 11 b) Yes since x 2 + 1000 ≤ x 2 + x 2 = 2x 2 for all x ≥ 32. d) No since x 4 /2 ≤ Cx 2 gives x 2 /2 ≤ C for all x, which cannot be true since we can always find a value of x beyond which this becomes false. 2. (E) 6 (x 3 + 2x)/(2x + 1) ≤ (x 3 + 2x 3 )/(2x) = (3/2)x 2 for all x ≥ 1 3. (E) 14acd a) No since x 3 ≤ Cx 2 gives x ≤ C for all x beyond some specific value, which cannot be true since we can always find an x beyond which C becomes smaller. c) Yes since x 3 ≤ x 2 + x 3 for all x. That is C = 1, k = 0. d) Yes since x 3 ≤ x 2 + x 4 for all x. That is C = 1, k = 0. 4. (E) 24ab a) x ≤ 3x + 7 for all x. On the other hand 3x + 7 ≤ 4x for all x ≥ 7. That is C = 4, k = 7. b) x 2 ≤ 2x 2 + x – 7 for x > 2. On the other hand 2x 2 + x – 7 ≤ 3x 2 for all x ≥ 1. That is C = 3, k = 1. 5. (E) 26

This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document
This is the end of the preview. Sign up to access the rest of the document.

## This note was uploaded on 01/28/2010 for the course EECS 203 taught by Professor Yaoyunshi during the Spring '07 term at University of Michigan.

### Page1 / 2

hw5 - EECS 203 Homework 5 Solutions Section 3.2 1(E 2abd a...

This preview shows document pages 1 - 2. Sign up to view the full document.

View Full Document
Ask a homework question - tutors are online