8. REASONING AND SOLUTIONThe centripetal acceleration for any point on the blade a distance rfrom center of the circle, according to Equation 5.2, is ac=v2/r. From Equation 5.1, we know that vrT=2π/where Tis the period of the motion. Combining these two equations, we obtain arTrrTc==(/)24222a. Since the turbine blades rotate at 617 rev/s, all points on the blades rotate with a period of T=(1/617) s = 1.62×10–3s. Therefore, for a point with
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