prob_010 - 10. REASONING The centripetal acceleration for...

Info iconThis preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
10. REASONING The centripetal acceleration for any point that is a distance r from the center of the disc is, according to Equation 5.2, a c = v 2 / r . From Equation 5.1, we know that vr T = 2 π / where T is the period of the motion. Combining these two equations, we obtain a rT r r T c == (/ ) 2 4 2 2 2 SOLUTION Using the above expression for a c , the ratio of the centripetal accelerations of the two points in question is a a 2 1 2 22 2 2 11 2 2 2 4 4 / / / / Since the disc is rigid, all points on the disc must move with the same period, so T 1 = T 2 . Making this cancellation and solving for
Background image of page 1
This is the end of the preview. Sign up to access the rest of the document.
Ask a homework question - tutors are online