10. REASONINGThe centripetal acceleration for any point that is a distance rfrom the center of the disc is, according to Equation 5.2, ac=v2/r. From Equation 5.1, we know that vrT=2π/where Tis the period of the motion. Combining these two equations, we obtain arTrrTc==(/)24222SOLUTIONUsing the above expression for ac, the ratio of the centripetal accelerations of the two points in question is aa21222221122244////Since the disc is rigid, all points on the disc must move with the same period, so T1=T2. Making this cancellation and solving for
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